MATH SOLVE

4 months ago

Q:
# I just need help for 3 questions!Write an expression for the perimeter of the triangle shown below: A triangle is shown with side lengths labeled 2.3x plus 14, 2x, and negative 0.2x plus 15.4.1x + 294.1x − 294.5x + 294.5x − 29 Which expression is equivalent to 1/5m − 20?1/5(m − 4)1/5(m − 100)5(m − 4)5(m − 100) Write an expression that is equivalent to 3/5 (3y + 15).three over fivey + 9three over five y + 15nine over fivey + 9nine over fivey + 15

Accepted Solution

A:

Answers:

1. a) 4.1x + 29

2. b) 1/5(m – 100)

3. c) nine over five y + 9 (9/5y + 9)

Explanations:

1. The formula for perimeter of a triangle is P = side a + side b + side c, so with these values it is:

2.3x + 14 + 2x – .2x + 15

Combine like terms:

4.1x + 29

2. Test the options to see which ones work out to the answer. You know that 1/5 of 100 = 20, so you need one with a 100 and a 1/5 in it. The only possible answer is:

1/5(m – 100)

3. Distribute the 3/5:

3/5 • 3y + 3/5 • 15 = 9/5y + 45/5 = 9/5y + 15

1. a) 4.1x + 29

2. b) 1/5(m – 100)

3. c) nine over five y + 9 (9/5y + 9)

Explanations:

1. The formula for perimeter of a triangle is P = side a + side b + side c, so with these values it is:

2.3x + 14 + 2x – .2x + 15

Combine like terms:

4.1x + 29

2. Test the options to see which ones work out to the answer. You know that 1/5 of 100 = 20, so you need one with a 100 and a 1/5 in it. The only possible answer is:

1/5(m – 100)

3. Distribute the 3/5:

3/5 • 3y + 3/5 • 15 = 9/5y + 45/5 = 9/5y + 15