The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5 . Suppose 49 golfers played the course today. Find the probability that the average score of the 49 golfers exceeded 62. A) .3707 B) .4772 C) .1293 D) .0228

Answer:The probability that the average score of the 49 golfers exceeded 62 is 0.3897Step-by-step explanation:The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5 [tex]\mu = 61[/tex][tex]\sigma = 3.5[/tex]We are supposed to find he probability that the average score of the 49 golfers exceeded 62.Formula : [tex]Z=\frac{x-\mu}{\sigma}[/tex][tex]Z=\frac{62-61}{3.5}[/tex][tex]Z=0.285[/tex]Refer the z table for p value p value = 0.6103P(x>62)=1-P(x<62)=1-0.6103=0.3897Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897